102地特-機械工程-熱力學第4題布雷登循環 - 考試
By Dora
at 2013-12-24T00:51
at 2013-12-24T00:51
Table of Contents
http://ppt.cc/H2im
※ 引述《avalon4 (Avalon)》之銘言:
: 問一下,布雷登循環那題,最低溫17℃(290K),最高溫827℃(1100K)
: 用等熵過程的T-V-P關係公式算完,K=5.1926/3.1156=1.67
: T1=190 K,那用等熵關式算出T2=1217 K
17℃=290 K
: T3=1100 K,用等熵關係式算出T4=171 K
: 題目給的溫度不是最高與最低溫,但 T1*T3=T2*T4
T1*T3=T2*T4? 怎麼得來的?
: 我在懷疑,那個題目給的190K是T4,1100K是T2
: 是我弄錯了嗎?有算出來的解惑一下。
: 原題目︰考處一氦氣(hELIUM)為工作流體之標準布雷登循環(Brayton),系統
: 壓縮機入口氣體壓力為90kPa,氣體壓縮比為16,系統最高與最低溫分別為
: 827℃及17℃。若氦氣質量流率為10kg/sec,試求此循環之︰
: (1)熱輸入量(kj/kg)
: (2)最大輸出功率
: (3)系統熱效率
: 註︰氦氣之氣體常數為2.0769 kJ/kgK,定壓比熱與定容比熱可視為常數,其值
: 分別為5.1926kJ/kgK與3.1156kJ/kgK
--
※ 引述《avalon4 (Avalon)》之銘言:
: 問一下,布雷登循環那題,最低溫17℃(290K),最高溫827℃(1100K)
: 用等熵過程的T-V-P關係公式算完,K=5.1926/3.1156=1.67
: T1=190 K,那用等熵關式算出T2=1217 K
17℃=290 K
: T3=1100 K,用等熵關係式算出T4=171 K
: 題目給的溫度不是最高與最低溫,但 T1*T3=T2*T4
T1*T3=T2*T4? 怎麼得來的?
: 我在懷疑,那個題目給的190K是T4,1100K是T2
: 是我弄錯了嗎?有算出來的解惑一下。
: 原題目︰考處一氦氣(hELIUM)為工作流體之標準布雷登循環(Brayton),系統
: 壓縮機入口氣體壓力為90kPa,氣體壓縮比為16,系統最高與最低溫分別為
: 827℃及17℃。若氦氣質量流率為10kg/sec,試求此循環之︰
: (1)熱輸入量(kj/kg)
: (2)最大輸出功率
: (3)系統熱效率
: 註︰氦氣之氣體常數為2.0769 kJ/kgK,定壓比熱與定容比熱可視為常數,其值
: 分別為5.1926kJ/kgK與3.1156kJ/kgK
--
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