104調查局 電腦網路 - 考試

By Olga
at 2016-06-25T21:07
at 2016-06-25T21:07
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考試
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By Dora
at 2016-06-26T17:57
at 2016-06-26T17:57
ze=2, 而stop and wait等於window size=1

By Thomas
at 2016-06-26T21:23
at 2016-06-26T21:23

By Regina
at 2016-06-28T11:07
at 2016-06-28T11:07

By Blanche
at 2016-06-28T19:14
at 2016-06-28T19:14
ime,前者是frame傳上通道的delay,後者是在通道中跑的delay
,因為加回送的ack,所以*2,而「通道利用率」就是通道中跑
的資料佔整個通道比例。1window就是一次一個frame上去,2w
indow就是可以連2frame上去「同一個通道」

By William
at 2016-06-29T19:28
at 2016-06-29T19:28

By Genevieve
at 2016-07-02T04:30
at 2016-07-02T04:30

By Zenobia
at 2016-07-02T15:34
at 2016-07-02T15:34
而分母的tp不用*2
求解qq

By Anthony
at 2016-07-07T09:50
at 2016-07-07T09:50

By Zora
at 2016-07-10T22:52
at 2016-07-10T22:52

By Queena
at 2016-07-15T17:27
at 2016-07-15T17:27
以用piggybacking一次傳2個seq,我覺得擬答是這個意思

By Anthony
at 2016-07-17T09:42
at 2016-07-17T09:42

By Caroline
at 2016-07-22T01:20
at 2016-07-22T01:20

By Lucy
at 2016-07-23T17:12
at 2016-07-23T17:12
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