-j8轉極座標 - 考試

By Michael
at 2013-03-21T22:56
at 2013-03-21T22:56
Table of Contents
請問書上的算式
-j8=8∠-90
我套用功式
0+(-8)平方開跟號乘∠tan-1(8/0)
答案算不出來會得到等號右邊的答案
但等號右邊如用又轉成直角座標8∠-90=8(cos-90+isin-90)又可以得到-j8
請問一下我哪裡錯了嗎?
感謝^^
--
-j8=8∠-90
我套用功式
0+(-8)平方開跟號乘∠tan-1(8/0)
答案算不出來會得到等號右邊的答案
但等號右邊如用又轉成直角座標8∠-90=8(cos-90+isin-90)又可以得到-j8
請問一下我哪裡錯了嗎?
感謝^^
--
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考試
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