功因一問(PF) - 考試
By Barb Cronin
at 2020-11-23T11:04
at 2020-11-23T11:04
Table of Contents
如題~綜所皆知,PF=cos(電壓角-電流角)
而此題的電壓角是要選送電端or受電端?
亦或是遇到題目如何判斷?
題目是用送電端的電壓角
鉛筆是用受電端的電壓角
感激不盡
https://i.imgur.com/wWehE9u.jpg
--
而此題的電壓角是要選送電端or受電端?
亦或是遇到題目如何判斷?
題目是用送電端的電壓角
鉛筆是用受電端的電壓角
感激不盡
https://i.imgur.com/wWehE9u.jpg
--
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