濃度觀念疑問 - 考試
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By Odelette
at 2013-08-07T15:29
at 2013-08-07T15:29
Table of Contents
※ [本文轉錄自 TransBioChem 看板 #1I0VRC8C ]
作者: nov123 (nov123) 看板: TransBioChem
標題: [化學] 濃度觀念疑問
時間: Wed Aug 7 15:27:06 2013
各位好,
有兩題關於計算濃度的觀念想請問大家,
1. 0.2M的醋酸 Ka=2x10^(-5); 0.2M的苯甲酸 Ka=3.5x10^(-5) 等體積混合
求[H+]濃度?
[H+]=[0.2x2x10^(-5)+0.23.5x10^(-5)]^(1/2)
=3.3x10^(-3)
2. 2M的HCl 和 1M的醋酸 等體積混合 求[H+]濃度?
設兩溶液皆為1升
2M*1升=[H+]*(1+1)升
[H+]=1M
請問為什麼 兩弱酸等體積混合,其[H+]不需再考慮等體積混合的體積變化?
而一強酸一弱酸等體積混合,其[H+]則考慮等體積混合的體積變化?
謝謝大家
--
作者: nov123 (nov123) 看板: TransBioChem
標題: [化學] 濃度觀念疑問
時間: Wed Aug 7 15:27:06 2013
各位好,
有兩題關於計算濃度的觀念想請問大家,
1. 0.2M的醋酸 Ka=2x10^(-5); 0.2M的苯甲酸 Ka=3.5x10^(-5) 等體積混合
求[H+]濃度?
[H+]=[0.2x2x10^(-5)+0.23.5x10^(-5)]^(1/2)
=3.3x10^(-3)
2. 2M的HCl 和 1M的醋酸 等體積混合 求[H+]濃度?
設兩溶液皆為1升
2M*1升=[H+]*(1+1)升
[H+]=1M
請問為什麼 兩弱酸等體積混合,其[H+]不需再考慮等體積混合的體積變化?
而一強酸一弱酸等體積混合,其[H+]則考慮等體積混合的體積變化?
謝謝大家
--
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