變壓器題目 - 考試
By Mia
at 2015-10-22T13:34
at 2015-10-22T13:34
Table of Contents
http://i.imgur.com/HaiyFrE.jpg
鐵損為磁滯損和渦流損之和
Ph=Kh*f*Bm^2
Pe=Ke*f^2*Bm^2*t^2
但是這題目好像沒有這些數據
看講義前面好像也沒有提到其他算法,有沒有人可以教我一下呢?
可以的話能連後面兩小題的效率也指導一下好嗎?感激不盡!!!
--
Sent from my Android
--
鐵損為磁滯損和渦流損之和
Ph=Kh*f*Bm^2
Pe=Ke*f^2*Bm^2*t^2
但是這題目好像沒有這些數據
看講義前面好像也沒有提到其他算法,有沒有人可以教我一下呢?
可以的話能連後面兩小題的效率也指導一下好嗎?感激不盡!!!
--
Sent from my Android
--
Tags:
考試
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at 2015-10-23T03:22
at 2015-10-23T03:22
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at 2015-10-24T05:32
at 2015-10-24T05:32
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at 2015-10-27T16:47
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at 2015-10-29T08:19
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at 2015-11-01T20:40
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