通訊系統歷屆考題數題 - 考試
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By Wallis
at 2013-07-31T22:13
at 2013-07-31T22:13
Table of Contents
[考題] 國考歷屆考題與考題觀念討論(書裡看到的選這個)請附上想法、出處
101警特三等
以下是考選部試題連結:
http://wwwc.moex.gov.tw/ExamQuesFiles/Question/101/101080_50950.pdf
第一題第二小題:
請問眼紋如何計算?網路上只查的到定義。
第四題:
(五)已求出R(τ)=1+100sinc(100τ)^2,而不相關則是R(τ)=1+100sinc(100τ)^2=0,
100sinc(100τ)^2=-1,這似乎是不可能?難道答案是怎麼取都相關?
96警特四等:
以下是考選部試題連結:
http://wwwc.moex.gov.tw/ExamQuesFiles/Question/096/017403400.pdf
第二題:
將x(t)轉為頻域為X(f)=0.25[δ(f-1)+δ(f+1)+δ(f+13)+δ(f-13)]
取樣後:x(t)Sigmaδ(t-n/10),
轉為頻域X(f)*10Sigmaδ(f+10n)=2.5[X(f-1+10n)+X(f+1+10n)
+X(f+13+10n)+X(f-13+10n)]
如此一來不就是無限多的δ函數?怎麼決定出最大與最小頻率呢?
第四題:
我的想法為:
(1)兩次都直接射出0,且無錯誤:0.4x0.4
(2)第一次射出0,第二次射出1,然後出錯變成0,又平均五位元錯一次,錯誤率為0.2:
0.4x(0.6x0.2)
(3)第一次射出1,出錯變成0,第二次射出0:(0.6x0.2)x0.4
(4)第一次射出1,出錯變成0,第二次射出1,出錯變成0:不會有此狀況。
將(1)、(2)、(3)相加即為解答。請問是否正確?
請知者能替我解惑,不吝指教或指正,謝謝。
--
101警特三等
以下是考選部試題連結:
http://wwwc.moex.gov.tw/ExamQuesFiles/Question/101/101080_50950.pdf
第一題第二小題:
請問眼紋如何計算?網路上只查的到定義。
第四題:
(五)已求出R(τ)=1+100sinc(100τ)^2,而不相關則是R(τ)=1+100sinc(100τ)^2=0,
100sinc(100τ)^2=-1,這似乎是不可能?難道答案是怎麼取都相關?
96警特四等:
以下是考選部試題連結:
http://wwwc.moex.gov.tw/ExamQuesFiles/Question/096/017403400.pdf
第二題:
將x(t)轉為頻域為X(f)=0.25[δ(f-1)+δ(f+1)+δ(f+13)+δ(f-13)]
取樣後:x(t)Sigmaδ(t-n/10),
轉為頻域X(f)*10Sigmaδ(f+10n)=2.5[X(f-1+10n)+X(f+1+10n)
+X(f+13+10n)+X(f-13+10n)]
如此一來不就是無限多的δ函數?怎麼決定出最大與最小頻率呢?
第四題:
我的想法為:
(1)兩次都直接射出0,且無錯誤:0.4x0.4
(2)第一次射出0,第二次射出1,然後出錯變成0,又平均五位元錯一次,錯誤率為0.2:
0.4x(0.6x0.2)
(3)第一次射出1,出錯變成0,第二次射出0:(0.6x0.2)x0.4
(4)第一次射出1,出錯變成0,第二次射出1,出錯變成0:不會有此狀況。
將(1)、(2)、(3)相加即為解答。請問是否正確?
請知者能替我解惑,不吝指教或指正,謝謝。
--
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