郵局營運職(系統分析)分數差太多? 複查? - 普考
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By Kyle
at 2013-07-16T14:13
at 2013-07-16T14:13
Table of Contents
請教各位前輩考友,
郵局 成績複查(只能各大題分數重加一次而已嗎? 感覺漏加分的可能性應不大!
可以針對內容嗎?還是有補救的其它方法 ) 因為覺得差太多!
不知有沒有考友也跟我一樣(因為我有準備高普考,所以覺得這些題目不難的...)
營運職---系統分析
我覺得我的專業科目2 資訊規劃與管理: 分數只有35分(自已覺得即使改得嚴
也有五、六十),因為每一題都會寫...不知大家都考幾分呢?
題一 (覺得蠻easy, 考古題都有
一 死結 (...)
二 四要件 non-preemptive hold-and-wait circular wait, mutual exclusive
三 如何預防 (打破以上二的問題去解決
題二 student 關聯表 (也蠻easy..,除非我的Answer 完全錯,不然分數至少有一半吧)
1nf(easy)
functional dependency 圖及找出所有相依性(我是劃 fk參考另一個關聯,拉一
條線,補習有教.. 主鍵也有列 ,忘記有沒劃ER-D)
2nf ....
3nf ... (有劃ER-D, 及列出所以表格 及主鍵..參照..)
我的3nf後的 ER-R 大約如下:
Student -n--<>-m-- Course ==m==<>--1--Professor
Student Student_Course Course Professor 四個關聯表
題三 ssl/tls , 請說明內含那幾個協定
(因不太確認, 就寫layer7 的 http imap ftp ssh ..有用到 ssl/tls的 layer7
協定,這樣對嗎? )
例子就以 web browser 上做 ssl 資料交換 交易...
先對稱式key加密內容 再pki公key將對稱式key加密, 兩都傳出
接收都依緒用pki私key解出對稱式key, 再解出內文..
...........
題四: 用表格寫出(雖沒有每一項都對,但對了六成,不會給零分吧??? 還是我的Answer 完全錯??? )
題四 : 私密性 完整性 可用性 不可否認性
RSA Y Y Y Y
AES Y Y Y N
DSA Y(應是N) Y(應是N) Y(應是N) N(應是Y)
MAC Y Y Y N
--
Tags:
普考
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