[鐵路104][資料通訊]第二題疑問 - 考試

By Erin
at 2015-06-27T14:39
at 2015-06-27T14:39
Table of Contents
我們有一電視頻道頻寬為 6 MHz,若我們用數位訊號傳送,並利用曼徹斯特編碼
(Manchester Encoding);若我們在電視頻道只傳送數位訊號的 1 個諧波(one
harmonic)、3 個諧波(three harmonics)或 5 個諧波(five harmonics),請問其各
別
傳送資料的最高速率為何?從上述結果,請申論通道頻寬、傳輸速率與訊號品質之
間的關係。
我寫的答案(就三個諧波的計算部分):
用Nyquist公式去計算
公式:2WlogM(二為底數)
N個諧波當作是2^N訊號層級
三個諧波 => logM = 3
M = 8
W = 6 X 10^6
2 X 6 X 10 ^ 6 X 3
= 36Mbps
這樣算是對的嗎?
祝大家金榜題名
--
(Manchester Encoding);若我們在電視頻道只傳送數位訊號的 1 個諧波(one
harmonic)、3 個諧波(three harmonics)或 5 個諧波(five harmonics),請問其各
別
傳送資料的最高速率為何?從上述結果,請申論通道頻寬、傳輸速率與訊號品質之
間的關係。
我寫的答案(就三個諧波的計算部分):
用Nyquist公式去計算
公式:2WlogM(二為底數)
N個諧波當作是2^N訊號層級
三個諧波 => logM = 3
M = 8
W = 6 X 10^6
2 X 6 X 10 ^ 6 X 3
= 36Mbps
這樣算是對的嗎?
祝大家金榜題名
--
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