電子學 MOSFET考慮ro時之電壓增益(已解) - 考試
By Hedy
at 2017-05-20T15:02
at 2017-05-20T15:02
Table of Contents
※ [本文轉錄自 alees 信箱]
e作者: hfjg9585 (相逢一笑) 看板: Examination
標題: Fw: [問題] MOSFET考慮ro時之電壓增益
時間: Fri May 19 12:20:23 2017
※ [本文轉錄自 Electronics 看板 #1P7cKvzM ]
作者: hfjg9585 (相逢一笑) 看板: Electronics
標題: [問題] MOSFET考慮ro時之電壓增益
時間: Fri May 19 11:23:35 2017
http://imgur.com/RKy3xfx
這題自己畫出等效小訊號模型進行推導,最後算出來是-5 (如下圖)
http://imgur.com/a/zolwu
但最後正解為-5.25
不知是否有別的方式或什麼重大觀念漏掉了導致推導不正確?
另外查到阿摩有個詳解為:
A= -1/ (1/gm+1) *RL = - 0.5*(21 // [1*(1+1*10)+10] )=-5.25
請問前面的 -1/(1/gm+1)是怎麼來的 謝謝
謝謝各位
--
e作者: hfjg9585 (相逢一笑) 看板: Examination
標題: Fw: [問題] MOSFET考慮ro時之電壓增益
時間: Fri May 19 12:20:23 2017
※ [本文轉錄自 Electronics 看板 #1P7cKvzM ]
作者: hfjg9585 (相逢一笑) 看板: Electronics
標題: [問題] MOSFET考慮ro時之電壓增益
時間: Fri May 19 11:23:35 2017
http://imgur.com/RKy3xfx
這題自己畫出等效小訊號模型進行推導,最後算出來是-5 (如下圖)
http://imgur.com/a/zolwu
但最後正解為-5.25
不知是否有別的方式或什麼重大觀念漏掉了導致推導不正確?
另外查到阿摩有個詳解為:
A= -1/ (1/gm+1) *RL = - 0.5*(21 // [1*(1+1*10)+10] )=-5.25
請問前面的 -1/(1/gm+1)是怎麼來的 謝謝
謝謝各位
--
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考試
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