102年普考基本電學 第二題 (求諾頓等效) - 普考
By Tom
at 2013-07-10T11:23
at 2013-07-10T11:23
Table of Contents
題目來源: 102年普考基本電學 第二題
http://ppt.cc/bJJH
這題對了一下補習班答案
(一)
老師A 他是有考慮電流源180mA
求得的a、b間的諾頓等效電路是
IN=-0.18A , RN=84歐姆
(二)
老師B 他只考慮電壓源24V 電流源560mA 而沒考慮電流源180mA
由重疊定理求得的a、b間的諾頓等效電路是
IN=-0.36A , RN=84歐姆
我的想法:
雖然我是求IN=-0.18A 但覺的好像老師B 沒考慮電流源180mA
求的IN=-0.36A是對的耶
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