102年高考電機機械第五題 - 高考
By Freda
at 2013-07-11T17:07
at 2013-07-11T17:07
Table of Contents
※ 引述《letterstar (letterstar)》之銘言：
: [考題] 國考歷屆考題與考題觀念討論(書裡看到的選這個)請附上想法、出處
: 題目:設有一50HP, 460V, 60Hz, 865rpm的三相感應
: 電動機,連至三相, 460v, 60Hz電源,於額定輸出
: 下運轉,此時輸入功率和輸入電流分別為43.75KW
: 和61A. 已知換算至定子側每相等效電路R1=0.1
: 歐姆,請額定轉述時的旋轉損失1050W,試求此感
: 應電動機滿載時的功率因數及效率, 轉子銅損,
: 鐵損?
: SOL:
: 功因=43.75KW/(3*265.58*61)=0.9
: 效率=(746*50)/43.75K=0.8526
: 可是題目沒有極數,就不能求轉速差,
: 還是有其他方法可以求轉子銅損和鐵損?
: 請各位高手解惑一下
: THX
[1] 若當題目問的鐵損為定子鐵心損 (這應該是題目所要問的)
http://ppt.cc/4kde
[2] 若當題目問的鐵損為轉子鐵心損
http://ppt.cc/gU5I
(可參考李進雲電機機械題庫集 95年地特三等第2題)
及參考李進雲四等歷屆試題 99年關務四等第4題)
--
: [考題] 國考歷屆考題與考題觀念討論(書裡看到的選這個)請附上想法、出處
: 題目:設有一50HP, 460V, 60Hz, 865rpm的三相感應
: 電動機,連至三相, 460v, 60Hz電源,於額定輸出
: 下運轉,此時輸入功率和輸入電流分別為43.75KW
: 和61A. 已知換算至定子側每相等效電路R1=0.1
: 歐姆,請額定轉述時的旋轉損失1050W,試求此感
: 應電動機滿載時的功率因數及效率, 轉子銅損,
: 鐵損?
: SOL:
: 功因=43.75KW/(3*265.58*61)=0.9
: 效率=(746*50)/43.75K=0.8526
: 可是題目沒有極數,就不能求轉速差,
: 還是有其他方法可以求轉子銅損和鐵損?
: 請各位高手解惑一下
: THX
[1] 若當題目問的鐵損為定子鐵心損 (這應該是題目所要問的)
http://ppt.cc/4kde
[2] 若當題目問的鐵損為轉子鐵心損
http://ppt.cc/gU5I
(可參考李進雲電機機械題庫集 95年地特三等第2題)
及參考李進雲四等歷屆試題 99年關務四等第4題)
--
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