102鐵特員級+97普考 基本電學 - 普考
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By Ophelia
at 2013-07-04T22:06
at 2013-07-04T22:06
Table of Contents
※ 引述《TFNF (帕妮飯)》之銘言:
: 1. 題目來源: 102鐵特員級第四題
: http://ppt.cc/CEq6
: 第一步先求戴維寧等效電阻,我算過好幾遍都是 19/11 歐姆
: 為何公職王提供的答案中 等效電阻為 29/17 歐姆??
: 算法如下:http://ppt.cc/15AG
剛有人寄mail問我怎麼算Eth
先把RL拿掉,如下圖
http://ppt.cc/7wCi
分析電路,Eth就是最右邊1歐姆的電壓,因RL被拿掉,右上角1歐姆無電流流過,
可以拿掉,如下圖
http://ppt.cc/uzMf
設節點電壓V
依KVL:
(V-5)/1 + (V-2Vx)/2 + v/(2+1)=0
Vx=5-v........代入上式得17V-60=0,V=60/17
Eth=60/17 * 1/(2+1)=20/17 (v)
--
: 1. 題目來源: 102鐵特員級第四題
: http://ppt.cc/CEq6
: 第一步先求戴維寧等效電阻,我算過好幾遍都是 19/11 歐姆
: 為何公職王提供的答案中 等效電阻為 29/17 歐姆??
: 算法如下:http://ppt.cc/15AG
剛有人寄mail問我怎麼算Eth
先把RL拿掉,如下圖
http://ppt.cc/7wCi
分析電路,Eth就是最右邊1歐姆的電壓,因RL被拿掉,右上角1歐姆無電流流過,
可以拿掉,如下圖
http://ppt.cc/uzMf
設節點電壓V
依KVL:
(V-5)/1 + (V-2Vx)/2 + v/(2+1)=0
Vx=5-v........代入上式得17V-60=0,V=60/17
Eth=60/17 * 1/(2+1)=20/17 (v)
--
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普考
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By Elma
at 2013-07-08T01:27
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