國營101年中油單操輸送 - 考試
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By Adele
at 2013-09-15T10:59
at 2013-09-15T10:59
Table of Contents
※ 引述《qq110 (袂森wii謀?!)》之銘言:
: 各位大家好:
: 想請問一下國營101年中油單操輸送題目:
: 題目如下:
: 題目:
: 半徑2mm,長10cm之毛細管內裝,密度0.865 g/cm3,黏度1.365 Pa*s 的流體,
: 若壓差為27cm H2O,求流體體積流量( m3/s )??(流體系統6個假設均成立)
: 請問這題是直接用 H-P eq'n帶入即可嗎??又6個假設成立是哪6個呢??
: 請化工或機械高手幫幫忙解答一下~~謝謝!
假設垂直管,流體向下流動
依據H-P eq
Q = [(π×R^4)/(8 ×viscosity)] ×[(壓力差/管長)×gc + density×g]
[3.14 ×(2 ×10^-3 m)^4] 27 ÷(76 ×13.6)×1.013×10^5 Pa
= ____________________________ ×________________________________ + 8477 Pa/m
8 ×1.365 Pa.s 0.1m
= 1.6 ×10^-7 m3/s
我也忘了去年我是假設平行管還是垂直管了=_=+
不過解題之前 最好先check Re Number,確定是Laminar Flow 以後再使用 H-P eq
反正假設寫清楚....剩下就給閱卷老師批囉
--
: 各位大家好:
: 想請問一下國營101年中油單操輸送題目:
: 題目如下:
: 題目:
: 半徑2mm,長10cm之毛細管內裝,密度0.865 g/cm3,黏度1.365 Pa*s 的流體,
: 若壓差為27cm H2O,求流體體積流量( m3/s )??(流體系統6個假設均成立)
: 請問這題是直接用 H-P eq'n帶入即可嗎??又6個假設成立是哪6個呢??
: 請化工或機械高手幫幫忙解答一下~~謝謝!
假設垂直管,流體向下流動
依據H-P eq
Q = [(π×R^4)/(8 ×viscosity)] ×[(壓力差/管長)×gc + density×g]
[3.14 ×(2 ×10^-3 m)^4] 27 ÷(76 ×13.6)×1.013×10^5 Pa
= ____________________________ ×________________________________ + 8477 Pa/m
8 ×1.365 Pa.s 0.1m
= 1.6 ×10^-7 m3/s
我也忘了去年我是假設平行管還是垂直管了=_=+
不過解題之前 最好先check Re Number,確定是Laminar Flow 以後再使用 H-P eq
反正假設寫清楚....剩下就給閱卷老師批囉
--
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考試
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By Wallis
at 2013-09-20T08:38
at 2013-09-20T08:38
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By Gary
at 2013-09-24T01:59
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at 2013-09-26T15:01
at 2013-09-26T15:01
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