基本電學 - 考試
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By Rae
at 2013-05-10T14:12
at 2013-05-10T14:12
Table of Contents
※ 引述《ginegibye (荊棘白)》之銘言:
: http://tinyurl.com/c9agd8r
: http://tinyurl.com/co345ey
: 48 49 50 56題
: 48、49題這種直流與交流混合的題目一直搞不太懂
把電壓源拆成直流和交流兩部份
100 100
I=----- + -------- = 5 + 4sin(wt-36.87)
20 20+j15
Iav = 5
積分(I平方)
Irms=根號(-------------) = 根號(25 + 8) = 根號(33)
2pi
delta接單相壞掉就變V接
: http://tinyurl.com/bw6qceq
: 這是56題我的想法
: 但P那邊除以3 是我後來湊出來的
: 為什麼不能用總功率 而是用單相的功率算呢
Q = 12000 * tan(cos-1(0.95)) = 3944.2
delta Q = 6000 - 3944.2 = 2055.8
題目沒寫清楚 不過看答案應該是單相電容器的虛功
2055.8 / 3 = 685
--
有沒有燒金紙的八卦?
→ oijkue:2F家燒掉了
--
: http://tinyurl.com/c9agd8r
: http://tinyurl.com/co345ey
: 48 49 50 56題
: 48、49題這種直流與交流混合的題目一直搞不太懂
把電壓源拆成直流和交流兩部份
100 100
I=----- + -------- = 5 + 4sin(wt-36.87)
20 20+j15
Iav = 5
積分(I平方)
Irms=根號(-------------) = 根號(25 + 8) = 根號(33)
2pi
delta接單相壞掉就變V接
: http://tinyurl.com/bw6qceq
: 這是56題我的想法
: 但P那邊除以3 是我後來湊出來的
: 為什麼不能用總功率 而是用單相的功率算呢
Q = 12000 * tan(cos-1(0.95)) = 3944.2
delta Q = 6000 - 3944.2 = 2055.8
題目沒寫清楚 不過看答案應該是單相電容器的虛功
2055.8 / 3 = 685
--
有沒有燒金紙的八卦?
→ oijkue:2F家燒掉了
→ andrewyllee:燒給一樓
--
Tags:
考試
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By Victoria
at 2013-05-12T05:35
at 2013-05-12T05:35
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at 2013-05-14T00:46
at 2013-05-14T00:46
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at 2013-05-15T02:50
at 2013-05-15T02:50
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By Andrew
at 2013-05-18T07:50
at 2013-05-18T07:50
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By Olivia
at 2013-05-21T13:39
at 2013-05-21T13:39
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By Bennie
at 2013-05-25T18:22
at 2013-05-25T18:22
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By Oliver
at 2013-05-27T16:14
at 2013-05-27T16:14
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at 2013-05-28T15:33
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