基本電學 - 考試
By Una
at 2013-06-08T06:00
at 2013-06-08T06:00
Table of Contents
[課業] 國考課業相關問題,非歷屆考題的討論,如學理觀念的釐清。
程金IE11版基本電學1題
http://ppt.cc/bBnT
答案是(A)
I有效值我算出來是約為4.9A
不是應該用Vrms/Z來算Irms的值嗎??請教一下
102年公務人員初等考試2題
http://ppt.cc/J-MY
Rth=8
請問這題的Rl開路電壓要怎麼看我有點搞混了
算出來我是算成4.5w
http://ppt.cc/YyKn
一直算不出答案-7V 請教一下這題用重疊還是迴流
程金IE11版基本電學1題
http://ppt.cc/bBnT
答案是(A)
I有效值我算出來是約為4.9A
不是應該用Vrms/Z來算Irms的值嗎??請教一下
102年公務人員初等考試2題
http://ppt.cc/J-MY
Rth=8
請問這題的Rl開路電壓要怎麼看我有點搞混了
算出來我是算成4.5w
http://ppt.cc/YyKn
一直算不出答案-7V 請教一下這題用重疊還是迴流
推 OPPLO:沒錯喔,V也要帶有效值,只是直流和交流要分開算,而直流是 06/08 07:34
→ OPPLO:100/20=5,交流是(100/根號2)/25=(4/根號2),平方相加開根號 06/08 07:36
→ OPPLO:就是答案了 06/08 07:36
→ funya:謝謝你 06/08 07:47
推 MJdavid:請用[考題]標題分類、附上出處想法 置底文有修改教學 感謝 06/08 10:04
→ alan3340:個人是算 8w 06/08 10:15
→ funya:請教一下你Eth的列式好嗎 06/08 10:41
→ funya:我懂了..腦筋打結轉不過來 06/08 10:59
※ 編輯: funya 來自: 1.169.219.237 (06/08 11:27) → wannapeace:接著用節電壓法列式: 06/08 11:37
→ wannapeace:(V+8/2) + V/2 + (V-8)/3 =0 06/08 11:37
→ wannapeace:整理得:V = -1(V) 06/08 11:38
→ wannapeace:題目欲求Vx = -8-(-1) = -7(V) 06/08 11:38
→ alan3340:2.你只是漏掉 2Ω 上的壓降 06/08 11:39
→ alan3340:3.先把電壓源全短路就會發現電流源完全不影嚮電路,再用 06/08 11:41
→ alan3340:KCL慢慢算即可 06/08 11:41
→ funya:了解了感恩 06/08 12:06
※ 編輯: funya 來自: 1.169.221.243 (06/08 19:19) 推 JSRF9999:借問一下第16題怎麼算 06/08 20:37
→ emuplayer:16題把1歐姆電阻拿掉求Eth=24-18=6V 06/08 21:03
推 JSRF9999:不懂24-18怎麼來的,電壓分配要怎樣才會到3:4? 06/09 10:02
→ JSRF9999:36V又要如何分配到18跟24V 06/09 10:11
→ emuplayer:36*6/(3+6)=24 ,36*6/(6+6)=18 ,Eth=24-18=6 06/09 14:58
→ emuplayer:Rth=(3//6) + (6//6) =5 ,放回原1歐姆可得到壓降 06/09 15:00
→ emuplayer:6* 1/(5+1)=1V 06/09 15:01
推 JSRF9999:推樓上~感謝解答,看來我的電學還是不行呀XD 06/09 18:02
→ JSRF9999:碰到有變化的就仆了=_=~ 06/09 18:02
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考試
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