基本電學 三相負載Y接△ - 考試
By Necoo
at 2014-03-24T17:33
at 2014-03-24T17:33
Table of Contents
題目:
http://i.imgur.com/4Yy87AD.jpg
想請教一下 相電壓/電流的部分
解答中
P=3VpIp cosΘ=> 3*300*30*0.6=16200w
Vp=300 和 Ip=30 到底怎麼算出的…。
相電壓不是等於Vp=100√3嗎?
麻煩版友們教一下,謝謝
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考試
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at 2014-03-27T10:37
at 2014-03-27T10:37
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at 2014-03-29T23:15
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