基本電學 三相負載Y接△ - 考試

By Necoo
at 2014-03-24T17:33
at 2014-03-24T17:33
Table of Contents
題目:
http://i.imgur.com/4Yy87AD.jpg
想請教一下 相電壓/電流的部分
解答中
P=3VpIp cosΘ=> 3*300*30*0.6=16200w
Vp=300 和 Ip=30 到底怎麼算出的…。
相電壓不是等於Vp=100√3嗎?
麻煩版友們教一下,謝謝
--
Tags:
考試
All Comments

By Tristan Cohan
at 2014-03-27T10:37
at 2014-03-27T10:37

By Andrew
at 2014-03-29T23:15
at 2014-03-29T23:15
Related Posts
基本電學-戴維寧換成諾頓

By Tristan Cohan
at 2014-03-24T16:23
at 2014-03-24T16:23
電機技師的實用性

By Jake
at 2014-03-24T15:46
at 2014-03-24T15:46
基本電學-戴維寧換成諾頓

By Charlotte
at 2014-03-24T15:15
at 2014-03-24T15:15
公職護理師服務證明

By Charlotte
at 2014-03-24T15:15
at 2014-03-24T15:15
程明的口訣

By Mia
at 2014-03-24T14:08
at 2014-03-24T14:08