基電 - 考試
By Lydia
at 2013-04-12T22:17
at 2013-04-12T22:17
Table of Contents
http://wwwc.moex.gov.tw/ExamQuesFiles/Question/101/101080_81040.pdf
第5題第1小項我算的結果
a.ZL=(4+j3)//-j3=3.75歐姆
Pmax=Emax^2/4*ZL=9.6w
b.ZL=5//-j3=2.57歐姆
Pmax=Emax^2/4*ZL=14w
兩種方式來驗證,怎算出結果不同,是我的觀念錯了嗎?
--
第5題第1小項我算的結果
a.ZL=(4+j3)//-j3=3.75歐姆
Pmax=Emax^2/4*ZL=9.6w
b.ZL=5//-j3=2.57歐姆
Pmax=Emax^2/4*ZL=14w
兩種方式來驗證,怎算出結果不同,是我的觀念錯了嗎?
--
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