普化 荷質比求原子量的問題 - 考試
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By Audriana
at 2011-01-15T00:38
at 2011-01-15T00:38
Table of Contents
題目:
某元素經質譜測得 X陽離子 之荷質比 = 5.08*10^3
又知某元素 X 只有一種穩定同位素,
則其原子量為若干克?
解答:
1 mole電子帶電量為1F = 96500 coul
96500/M = 5.08*10^3
M = 19g/mole
我想問的是題目說:「又知某元素X只有一種穩定同位素」
這句話要怎麼解讀呢?
按照題意看起來 元素X 總共會有兩種原子序相同,但質量數不同的原子,
代表元素X的同位素質量不會相同,
依照解答這樣算,為什麼能算出元素X的原子量呢?
唉唉,它若不要加那句的話,我還知道怎麼解說...
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By Olga
at 2011-01-19T22:33
at 2011-01-19T22:33
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By Kyle
at 2011-01-21T18:44
at 2011-01-21T18:44
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