熱力學 brayton燃機問題 - 高考
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By Audriana
at 2013-06-26T09:49
at 2013-06-26T09:49
Table of Contents
[考題] 國考歷屆考題與考題觀念討論(書裡看到的選這個)請附上想法、出處
各位大大 您好,
想請教一下,在brayton cycle中,進出燃料室的相關計算,如下圖說明
2
| --------
(m2)fuel --> | |
(m1)air --> |燃燒室| --> (m3) 渦輪機
| -------- |
1 3
因為我看圖片,燃料都是在鎗內與空氣燃燒, 故反應前後總質量守衡
=> m1 + m2 = m3
那麼進出燃料室的能量守衡應該表示為 :
[Q13 + Q23] = m1 * Cp * (T3 - T1) + m2 * Cp * (T3 - T2)
因為熱是燃料所提供(Q23),而空氣沒有(Q13)
那 T2 = ??
相關題目 :
高考 100年 Q2 http://wwwc.moex.gov.tw/ExamQuesFiles/Question/100/100120_34020.pdf
地特 095年 Q3 http://wwwc.moex.gov.tw/ExamQuesFiles/Question/095/024332200.pdf
懇請板上前輩不吝指點
感謝
--
各位大大 您好,
想請教一下,在brayton cycle中,進出燃料室的相關計算,如下圖說明
2
| --------
(m2)fuel --> | |
(m1)air --> |燃燒室| --> (m3) 渦輪機
| -------- |
1 3
因為我看圖片,燃料都是在鎗內與空氣燃燒, 故反應前後總質量守衡
=> m1 + m2 = m3
那麼進出燃料室的能量守衡應該表示為 :
[Q13 + Q23] = m1 * Cp * (T3 - T1) + m2 * Cp * (T3 - T2)
因為熱是燃料所提供(Q23),而空氣沒有(Q13)
那 T2 = ??
相關題目 :
高考 100年 Q2 http://wwwc.moex.gov.tw/ExamQuesFiles/Question/100/100120_34020.pdf
地特 095年 Q3 http://wwwc.moex.gov.tw/ExamQuesFiles/Question/095/024332200.pdf
懇請板上前輩不吝指點
感謝
--
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高考
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