物理斜拋 - 考試
By Olive
at 2015-03-11T01:09
at 2015-03-11T01:09
Table of Contents
設重力加速度大小為10m/s^2,
在地面上以初速度30m/s、仰角30度將一球拋出,則其水平射程為多少m? (A)45 (B)45 根號3 (C)90 (D)90根號3
以下是我算的:
Vx=15根號3
Vy=15
15=1/2*10*t^2
t=根號3,T=2根號3
X=15根號3*2根號3=90
但答案是(B)45 根號3
想破頭了,不知錯再在哪?
求解,感謝!
--
在地面上以初速度30m/s、仰角30度將一球拋出,則其水平射程為多少m? (A)45 (B)45 根號3 (C)90 (D)90根號3
以下是我算的:
Vx=15根號3
Vy=15
15=1/2*10*t^2
t=根號3,T=2根號3
X=15根號3*2根號3=90
但答案是(B)45 根號3
想破頭了,不知錯再在哪?
求解,感謝!
--
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