直線運動-加速度問題 - 考試

By Jack
at 2014-02-02T20:55
at 2014-02-02T20:55
Table of Contents
※ [本文轉錄自 Math 看板 #1Ixa0JKm ]
作者: pigheadthree () 看板: Math
標題: [其他] 直線運動-加速度問題
時間: Sun Feb 2 20:54:41 2014
版上前輩們您好!
有關於直線運動上的應用公式如下:
v = v0 + a*t
s-s0 = v0*t + (1/2)*a*t^(2)
v^(2) = v0^(2) + 2*a*(s-s0)
在計算例題中,發現自由落體a(加速度)運算我們使用-9.81m/sec^2
直線運動當中 s = 時間方程式
v = s一次微分
a = s二次微分
請問,假設我們運用上述的應用公式,在直線運動當中 a=-9.81m/sec^2
還是使用 a=9.81m/sec^2 ???
麻煩不吝嗇指導,謝謝!
--
作者: pigheadthree () 看板: Math
標題: [其他] 直線運動-加速度問題
時間: Sun Feb 2 20:54:41 2014
版上前輩們您好!
有關於直線運動上的應用公式如下:
v = v0 + a*t
s-s0 = v0*t + (1/2)*a*t^(2)
v^(2) = v0^(2) + 2*a*(s-s0)
在計算例題中,發現自由落體a(加速度)運算我們使用-9.81m/sec^2
直線運動當中 s = 時間方程式
v = s一次微分
a = s二次微分
請問,假設我們運用上述的應用公式,在直線運動當中 a=-9.81m/sec^2
還是使用 a=9.81m/sec^2 ???
麻煩不吝嗇指導,謝謝!
--
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考試
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