簡單工程經濟問題 - 金融分析師
By Elvira
at 2011-11-22T00:18
at 2011-11-22T00:18
Table of Contents
不好意思打擾各位了 我想請教一題工程經濟 (or 利率學) 的問題
不知道在此問問題是否恰當 如不適合請多多包涵 m(_ _)m
題目如下:What the present worth of the following cash flows?
$30000 for the first year and decreasing by $1500 for
each of the next 8 year at 8%.
我的想法:
(1) 期初:第1年初 $30000 收入,第2年到第9年初,每年遞減1500
故 PW = 30000 + 28500(P/F,8%,1)
+ 27000(P/F,8%,2) + 25500(P/F,8%,3)
+ 24000(P/F,8%,4) + 22500(P/F,8%,5)
+ 21000(P/F,8%,6) + 19500(P/F,8%,7)
+ 18000(P/F,8%,8)
= 167070.062
(2) 期末:第1年末 $30000 收入,第2年到第9年末,每年遞減1500
故 PW = 30000(P/F,8%,1) + 28500(P/F,8%,2)
+ 27000(P/F,8%,3) + 25500(P/F,8%,4)
+ 24000(P/F,8%,5) + 22500(P/F,8%,6)
+ 21000(P/F,8%,7) + 19500(P/F,8%,8)
+ 18000(P/F,8%,9)
= 154694.502
但書本的答案卻是 $220125 不知道是不是我哪裡意會錯了?謝謝!
--
不知道在此問問題是否恰當 如不適合請多多包涵 m(_ _)m
題目如下:What the present worth of the following cash flows?
$30000 for the first year and decreasing by $1500 for
each of the next 8 year at 8%.
我的想法:
(1) 期初:第1年初 $30000 收入,第2年到第9年初,每年遞減1500
故 PW = 30000 + 28500(P/F,8%,1)
+ 27000(P/F,8%,2) + 25500(P/F,8%,3)
+ 24000(P/F,8%,4) + 22500(P/F,8%,5)
+ 21000(P/F,8%,6) + 19500(P/F,8%,7)
+ 18000(P/F,8%,8)
= 167070.062
(2) 期末:第1年末 $30000 收入,第2年到第9年末,每年遞減1500
故 PW = 30000(P/F,8%,1) + 28500(P/F,8%,2)
+ 27000(P/F,8%,3) + 25500(P/F,8%,4)
+ 24000(P/F,8%,5) + 22500(P/F,8%,6)
+ 21000(P/F,8%,7) + 19500(P/F,8%,8)
+ 18000(P/F,8%,9)
= 154694.502
但書本的答案卻是 $220125 不知道是不是我哪裡意會錯了?謝謝!
--
Tags:
金融分析師
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at 2011-11-26T02:45
at 2011-11-26T02:45
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