通訊系統歷屆考題數題 - 考試
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By Harry
at 2013-08-14T20:57
at 2013-08-14T20:57
Table of Contents
[考題] 國考歷屆考題與考題觀念討論(書裡看到的選這個)請附上想法、出處
98年電子技師:
以下連結為考選部考畢試題:
http://wwwc.moex.gov.tw/ExamQuesFiles/Question/098/035012300.pdf
第五題:
(一)Pr=Pt+Gt-自由路徑損耗+Gr
=20+17-195.6+39
=-119.6 (dB)
(二)Pr=Eb x Tb=Eb(dB)+Tb(dB)
-119.6=-193.9+Tb
Tb=74.3(dB)
Rb=-74.3(dB)
滿懷疑我的答案的,因為這樣算起來位元傳輸率很低,以實務來說很不正常吧?
請替我檢驗是否哪裡出錯了,謝謝。
=============================================================================
94年電子技師:
以下連結為考選部考畢試題:
http://wwwc.moex.gov.tw/ExamQuesFiles/Question/094/036312300.pdf
第二題:
(二)我求出的Huffman code為:A 00 B 11 C 011 D 010 E 10
Lbar=2x0.3+2x0.2+3x0.1+3x0.15+2x0.25
接著我就不知道題目的意思了@@"
謝謝。
--
98年電子技師:
以下連結為考選部考畢試題:
http://wwwc.moex.gov.tw/ExamQuesFiles/Question/098/035012300.pdf
第五題:
(一)Pr=Pt+Gt-自由路徑損耗+Gr
=20+17-195.6+39
=-119.6 (dB)
(二)Pr=Eb x Tb=Eb(dB)+Tb(dB)
-119.6=-193.9+Tb
Tb=74.3(dB)
Rb=-74.3(dB)
滿懷疑我的答案的,因為這樣算起來位元傳輸率很低,以實務來說很不正常吧?
請替我檢驗是否哪裡出錯了,謝謝。
=============================================================================
94年電子技師:
以下連結為考選部考畢試題:
http://wwwc.moex.gov.tw/ExamQuesFiles/Question/094/036312300.pdf
第二題:
(二)我求出的Huffman code為:A 00 B 11 C 011 D 010 E 10
Lbar=2x0.3+2x0.2+3x0.1+3x0.15+2x0.25
接著我就不知道題目的意思了@@"
謝謝。
--
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