電磁學 映像法靜電能 - 考試
By Jake
at 2016-06-14T15:11
at 2016-06-14T15:11
Table of Contents
問題:
無限大接地平面,電荷q被放在(x,y,z)=(0,d,0),
請問此系統的靜電能為多少? (某年114電子所)
我的解法是,使用映像法
q‧
│ d
等效後 -------------
│ d
-q‧
所以靜電能為 We = -q * [q / 4piε*(2d)] = -q^2/8piεd
但李長綱講義的解答為 We = -q^2/16piεd
剛好是我算的一半,請問我錯在哪裡呢?
--
無限大接地平面,電荷q被放在(x,y,z)=(0,d,0),
請問此系統的靜電能為多少? (某年114電子所)
我的解法是,使用映像法
q‧
│ d
等效後 -------------
│ d
-q‧
所以靜電能為 We = -q * [q / 4piε*(2d)] = -q^2/8piεd
但李長綱講義的解答為 We = -q^2/16piεd
剛好是我算的一半,請問我錯在哪裡呢?
--
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考試
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