基本電學 - 考試
By Suhail Hany
at 2013-05-05T18:55
at 2013-05-05T18:55
Table of Contents
※ 引述《johntu (TB)》之銘言：
: R-L 串聯電路中, 一個時間常數即線路電流自初狀變化至穩態時之
: (A) 36.8% (B)63.2% (C)100% (D)13.5%
: 答案為B, 請問這要怎麼判斷呢?
1L/R=?
假設一個串聯電路 R=10 L=10 H V=10V 1L/R=1*10/10=1s
電流穩定狀態I=10/10(1-e^-∞)=10/10(1-0)=1 A
電流初態I=10/10(1-e^-1)=10/10(1-0.368)=0.632A
用上面了解 一個時間常數即電流初狀(0.632A)變化至穩態時(1A)之63.2%
Q1:時間常數跟電流變化之關係要怎麼看?
Q2:看板友將初狀假設為t=1s，為什麼呢?
有請高手講解了~ 感謝~
--
: R-L 串聯電路中, 一個時間常數即線路電流自初狀變化至穩態時之
: (A) 36.8% (B)63.2% (C)100% (D)13.5%
: 答案為B, 請問這要怎麼判斷呢?
1L/R=?
假設一個串聯電路 R=10 L=10 H V=10V 1L/R=1*10/10=1s
電流穩定狀態I=10/10(1-e^-∞)=10/10(1-0)=1 A
電流初態I=10/10(1-e^-1)=10/10(1-0.368)=0.632A
用上面了解 一個時間常數即電流初狀(0.632A)變化至穩態時(1A)之63.2%
Q1:時間常數跟電流變化之關係要怎麼看?
Q2:看板友將初狀假設為t=1s，為什麼呢?
有請高手講解了~ 感謝~
--
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考試
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