機件原理-齒輪齒數計算 - 考試

By Edith
at 2017-01-24T12:04
at 2017-01-24T12:04
Table of Contents
兩互相嚙合之正齒輪,轉向相反,模數為5,轉速比為3:2,中心距離為250mm,則大齒輪
齒數為多少?
兩互相嚙合之正齒輪模數相同,故M皆為5
公式:
C = (D1-D2) / 2
= (T1-T2) * PC / 2拍
= (T1-T2) * M /2
然後就卡住不知該怎計算了 = =?
--
齒數為多少?
兩互相嚙合之正齒輪模數相同,故M皆為5
公式:
C = (D1-D2) / 2
= (T1-T2) * PC / 2拍
= (T1-T2) * M /2
然後就卡住不知該怎計算了 = =?
--
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