電子學 濾波器 - 考試
By Olive
at 2016-05-16T11:44
at 2016-05-16T11:44
Table of Contents
有一Butterworth 濾波器
|H(f=6)| = Ho/根號(1+4^N) = 20logHo - 20log根號(1+4^N)
20dB = 20log根號(1+4^N)
請問第一行怎麼推到第二行?
謝謝
--
|H(f=6)| = Ho/根號(1+4^N) = 20logHo - 20log根號(1+4^N)
20dB = 20log根號(1+4^N)
請問第一行怎麼推到第二行?
謝謝
--
Tags:
考試
All Comments
By Tom
at 2016-05-19T09:03
at 2016-05-19T09:03
Related Posts
ARP reply封包內容
By Olga
at 2016-05-16T11:14
at 2016-05-16T11:14
請問阿摩用手機搜尋選擇為什麼變電腦版
By Quanna
at 2016-05-16T09:28
at 2016-05-16T09:28
警特跟鐵特考場有冷氣?
By Caroline
at 2016-05-16T08:38
at 2016-05-16T08:38
行程法118
By Gilbert
at 2016-05-16T05:26
at 2016-05-16T05:26
兩個月有機會考上監所嗎?(有一半底子)
By Donna
at 2016-05-15T22:36
at 2016-05-15T22:36