台灣菸酒98年新進從業人員分析化學第三題 - 考試
By Elizabeth
at 2013-10-01T08:57
at 2013-10-01T08:57
Table of Contents
Cd2+與NH3 溶液的反應如下:Cd2+ + 4NH3 -> Cd[(NH3)4]2+ β4 = 3.6 x 10^6
有一1.0M NH3 溶液含有0.10 M Cd(II),試計算陽極(cathode)的電壓須為何,才
能還原溶液中99.99%的Cd(II)。Cd2+的還原電位E0(Cd2+/Cd) = -0.402V,而使用
的陰極為標準氫電極(S.H.E)。
請問各位高手這題該如何計算,能斯特方程式???
--
有一1.0M NH3 溶液含有0.10 M Cd(II),試計算陽極(cathode)的電壓須為何,才
能還原溶液中99.99%的Cd(II)。Cd2+的還原電位E0(Cd2+/Cd) = -0.402V,而使用
的陰極為標準氫電極(S.H.E)。
請問各位高手這題該如何計算,能斯特方程式???
--
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